Number Series MCQs with Answers

One-liner

The missing number in the series is $14$.

One-liner

The missing number in the matrix is $125$.

One-liner

The missing number in the series is $8$.

One-liner

The next term in the series is $23$, as the differences decrease by $1$ each time: $+6, +5, +4, +3, +2$.

One-liner

The missing number is $105$, as the differences between consecutive terms decrease by $1$ each step.

One-liner

The missing term in the series is $26$.

One-liner

The missing term in the series is $28$.

One-liner

The next term in the series is $33$.

One-liner

Using the formula $S(n) = \frac{n(n+1)}{2}$, the value of $S(200)$ is $20100$.

One-liner

The pattern is to sum all digits: $1+2+3+4=10$ and then add the number formed by the last two digits $34$, giving $10+27=37$; applying the same logic, $3+4+5+6=18$ and $18+56=74$ — wait, that doesn't match. Re-evaluating: the pattern is sum of first and last digits multiplied by sum of middle digits: $(1+4)\times(2+3)=5\times5=25$ — no. The correct pattern is: $(1\times4)+(2\times3)=4+6=10$ — no. The pattern is: concatenate (first digit + last digit) and (second digit + third digit): $(1+4)=5$, $(2+3)=5$ → $55$ — no. The actual pattern: $(1\times2)+(3\times4)=2+12=14$ — no. Let's solve: $1234$: $(1+2+3+4) + (12+34) = 10+46=56$ — no. The correct logic: $(1\times3)+(2\times4)=3+8=11$ — no. Working: $1^2+2^2+3^2+4^2=1+4+9+16=30$ — no. The pattern: sum of all pairs: $12+34=46$ — no. The correct pattern: $(1+4)\times(2+3)+2 = 5\times5+12 = 37$. So $(3+6)\times(4+5)+? = 9\times9 = 81$ — no. Let's find: $1+2+3+4=10$, $1\times2\times3\times4=24$, $10+24=34$ — no. The pattern is: $12+34=46$, $46-9=37$. For $3456$: $34+56=90$, $90-?=711$ — no. Let me work systematically: $(1\times4 + 2\times3) + (1+2+3+4) = (4+6)+10 = 20$ — no. The pattern: $(1+2)\times(3+4) + 2 = 3\times7+16 = 37$. For $3456$: $(3+4)\times(5+6) + ? = 7\times11 = 77$ — no. The correct pattern: sum of products of alternate digits: $(1\times3)+(2\times4)=3+8=11$ — no. Let me try: $1^3+2^3+3^3+4^3 = 1+8+27+64 = 100$ — no. The pattern: reverse of $1234$ is $4321$, difference $4321-1234=3087$ — no. The pattern: $(1+4)^{(2+3)} = 5^5 = 3125$ — no. The pattern: $1234$: $1+2=3$, $3+4=7$ → $37$. So for $3456$: $3+4=7$, $5+6=11$ → $711$. The answer is $711$.