Asked in PPSC, FPSC and other one-paper exams (compiled from unofficial resources).
AlgebraExponents and Powers
If $1 < x < 2$, then the value of $\sqrt{(x - 1)^2} + \sqrt{(3 - x)^2}$ is:
- A.$2$Correct answer
- B.$4$
- C.$2x - 4$
- D.$4 - 2x$
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Practice these MCQs in the appQuick fact: The value of the expression simplifies to $2$ because $\sqrt{(x-1)^2}=x-1$ and $\sqrt{(3-x)^2}=3-x$ for $1<x<2$.